After making my post #59, I decided that it would make sense to compute the power split between the "direct" mechanical path to/from the ICE and the indirect path through the two MGs in all the basically different modes of operation that I had illustrated in my posts #27 and 34. This turned out to be a very interesting and instructive exercise (well, to me at least!). I'll repeat the information from my post #59 again here for completeness.
I shall assume, as I did before, that no battery charging is taking place (it's "full" say), and that the MGs are 100% efficient in their energy conversion (this isn't seriously wrong — they are apparently ~95% efficient at each conversion between mechanical and electrical energy, so that their back-to-back conversion efficiency is ~90%). Then I can calculate the energy flow and split using the following formula:
Pe =
Ne .
Te = (0.7222
Nr + 0.2778
Ns) .
Te
which can be derived from the
Formulas page in my earlier posting. Here:
Pe is the ICE power (positive if the ICE is supplying power to the wheels, and negative if the ICE is absorbing power from the wheels during fuel-cut engine braking);
Te is the ICE's output shaft torque (positive if the ICE is supplying power to the wheels, and negative if the ICE is absorbing power from the wheels during fuel-cut engine braking) — we don't need to know the
value of
Te, only its
sign which we can read off the nomograms;
Nr is the ring-gear speed in rpm (positive if the car is moving forwards, and negative if it's moving backwards); and
Ns is the sun-gear speed in rpm (positive if MG1 is rotating forwards, and negative if it's rotating backwards).
I will examine the following four scenarios using data from my
Table:
- Figure B — "Normal" mode: Transmission in 'D'
RS = 120 km/h (~75 miles per hour) (this is the Road Speed)
Ne = 3000 rpm
Te > 0
Nr = +3386 rpm
Ns = +1995 rpm
Pe = 3000 . Te = (2446 + 554) . Te > 0 (81.5% + 18.5% = 100%)
- Figure C — "Heretical" mode: Transmission in 'D'
RS = 120 km/h (~75 miles per hour)
Ne = 2000 rpm
Te > 0
Nr = +3386 rpm
Ns = -1605 rpm
Pe = 2000 . Te = (2446 - 446) . Te > 0 (122.3% - 22.3% = 100%)
- Figure G — "Fuel-cut" coasting: Transmission in 'D'
RS = 120 km/h (~75 miles per hour)
Ne = 1000 rpm
Te < 0
Nr = +3386 rpm
Ns = -5205 rpm
Pe = 1000 . Te = (2446 - 1446) . Te < 0 (-244.6% + 144.6% = -100%)
- Figure I — "Fuel-cut" engine braking: Transmission in 'B'
RS = 100 km/h (~62 miles per hour)
Ne = 3000 rpm
Te < 0
Nr = +2822 rpm
Ns = +3463 rpm
Pe = 3000 . Te = (2038 + 962) . Te < 0 (-67.9% - 32.1% = -100%)
In each case I show in parentheses two percentages: (a) the percentage of the total ICE power that flows to the wheels
mechanically directly through the planetary-gear set from the planetary-carrier (i.e., the ICE) to the ring-gear (or
vice versa); and (b) the percentage that flows
electrically from the sun-gear (i.e., MG1) to the ring-gear (i.e., MG2) (or
vice versa). Negative percentages represent reverse power flow.
We see:
- Figure B — "Normal" mode: Transmission in 'D'
Here power flows from the ICE to the wheels, 81.5% of it mechanically and 18.5% of it electrically.
- Figure C — "Heretical" mode: Transmission in 'D'
Here 22.3% of the mechanical power flows back into the planetary-gear set electrically from MG2 to MG1, leaving, of course, a net total of 100% at the wheels. That's why it was dubbed "heretical" mode!
- Figure G — "Fuel-cut" coasting: Transmission in 'D'
Here 244.6% of the engine braking power flows directly from the wheels to the ICE through the planetary-gear set, while interestingly 144.6% of the power actually flows forwards electrically from MG1 to MG2, leaving, of course, a net total of -100% at the wheels. MG1 acts as a generator and MG2 as a motor here.
- Figure I — "Fuel-cut" engine braking: Transmission in 'B'
Here 67.9% of the engine braking power flows directly from the wheels to the ICE through the planetary-gear set, while 32.1% of the power flows electrically from MG2 to MG1, leaving, of course, a net total of -100% at the wheels. MG2 acts as a generator and MG1 as a motor here.
Notice how all sign possibilities are accounted for in these four cases: +/+; +/-; -/+; -/- respectively (recall that
Te is negative in the last two cases!).
Stan